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5x^2+5x=2100
We move all terms to the left:
5x^2+5x-(2100)=0
a = 5; b = 5; c = -2100;
Δ = b2-4ac
Δ = 52-4·5·(-2100)
Δ = 42025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{42025}=205$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-205}{2*5}=\frac{-210}{10} =-21 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+205}{2*5}=\frac{200}{10} =20 $
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